Sand Lake is safer than the majority of cities, towns, and villages in America (66%) and also has a lower crime rate than 63% of the communities in Michigan, according to NeighborhoodScout's analysis of FBI crime data. How risky is that? Your chance of becoming a victim in Sand Lake is one in 158 based on the total crime rate (violent and property crimes, combined). In America overall, your chance of becoming a victim of crime is 1 in 43.

However, when you compare Sand Lake to other communities of similar population, then Sand Lake crime rate (violent and property crimes combined) is quite a bit higher than average. Regardless of how Sand Lake does relative to all communities in America of all sizes, when NeighborhoodScout compared it to communities of similar population size, its crime rate per thousand residents stands out as higher than most.

Now let us turn to take a look at how Sand Lake does for violent crimes specifically, and then how it does for property crimes. This is important because the overall crime rate can be further illuminated by understanding if violent crime or property crimes (or both) are the major contributors to the general rate of crime in Sand Lake.

From our analysis, we discovered that violent crime in Sand Lake occurs at a rate higher than in most communities of all population sizes in America. The chance that a person will become a victim of a violent crime in Sand Lake; such as armed robbery, aggravated assault, rape or murder; is 1 in 473. This equates to a rate of 2 per one thousand inhabitants.

NeighborhoodScout's analysis of property crime reveals that the property crime rate in Sand Lake is below average to all cities and towns in the nation. This means that you are less likely to become a victim of arson, motor vehicle theft, larceny, or burglary in Sand Lake than in most communities in America. Your chance of becoming a victim of property crime if you live here? Just one in 237.